Methods2025 NHT Exam 2 Section A · Q4CAS active1 mark

Graph of an antiderivative from a linear graph

The graph of $y = f(x)$ is shown below.

A straight line y = f(x) with negative gradient, crossing the positive y-axis and cutting the x-axis at x = 1.

Option A: an upward-opening parabola with its minimum turning point at x = 1, below the x-axis, crossing the x-axis on both sides of the origin.

Option B: a downward-opening parabola with its maximum turning point at x = 1, above the x-axis, crossing the x-axis on both sides of the origin.

Which option shows the graph of $y = F(x)$ , where $F$ is an anti-derivative of $f$ ?

1 mark

A(graph) Upward-opening parabola with a minimum at

x = 1

B(graph) Downward-opening parabola with a maximum at

x = 1

C(graph) Upward-opening parabola with a minimum at

x = -1

D(graph) Downward-opening parabola with a maximum at

x = -1

Hints, answer checking and worked solutions come with a Season Pass.