Specialist2026 NHT Exam 2 Section A · Q8CAS active1 mark

Parametric curve: value of t for a given gradient

A curve is described parametrically by $x = \sin(t)$ , $y = \sec(t)$ , where $-\frac{\pi}{2} < t < \frac{\pi}{2}$ .

The exact value of $t$ , where $\frac{dy}{dx} = 4\sqrt{3}$ , is

1 mark

\frac{\pi}{6}

1.047

\frac{\pi}{3}

\tan^{-1}\left(4\sqrt{3}\right)

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