Specialist2026 NHT Exam 2 Section A · Q7CAS active1 mark

Matching a direction field to a differential equation

A direction field on axes from x = −2 to 2 and y = −2 to 2. Slopes are steep and negative in the upper left, steep and positive in the lower right, and horizontal along the line y = x.

The direction field above best represents the differential equation

1 mark

\frac{dy}{dx} = y - x

\frac{dy}{dx} = x - y

\frac{dy}{dx} = \frac{1}{x - y}

\frac{dy}{dx} = \frac{1}{y - x}

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