Methods2024 NHT Exam 2 Section A · Q1CAS active1 mark

Period and range of a sine function

The period and range for the function $f(x) = \sqrt{3}\sin\left(2x - \frac{\pi}{2}\right) - \sqrt{3}$ are respectively

1 mark

\pi

and

\left[-\sqrt{3}, \sqrt{3}\right]

2\pi

and

\left[-\sqrt{3}, \sqrt{3}\right]

\pi

and

\left[-2\sqrt{3}, 0\right]

2\pi

and

\left[-2\sqrt{3}, 0\right]

4\pi

and

\left[-2\sqrt{3}, 0\right]

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