Specialist2024 NHT Exam 2 Section A · Q16CAS active1 mark

Velocity perpendicular to acceleration

The position vector $\tvec{r}(t)$ of a particle at time $t$ is given by $\tvec{r}(t) = e^{-4t}\tvec{i} + e^{t}\tvec{j}$ , $t \ge 0$ .

The value of $t$ when the particle's velocity is perpendicular to its acceleration is

1 mark

\frac{1}{5}\log_e(64)

\frac{1}{2}\log_e(2)

\frac{1}{6}\log_e(32)

\frac{3}{5}\log_e(2)

\frac{1}{4}\log_e(64)

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